Question

Physics

A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt2+qt, with p = 0.36 m/s2and q = -1.40 m/s .

Determine the mouse's average speed between t = 1.0 s and t = 4.0 s.

I have tried everything and the answer is not 0.40 m/s

<Homework 1 Item 17 A mouse runs along a baseboard in your house. The mouse's position v0.40 m/s î as a function of time is given by x(t) = pt2 + qt, with p 0.36 m/s and q -1.40 m/s Previous Answers Submit Correct Part D Determine the mouse's average speed between t 1.0 s and t 4.0 s. Π ΑΣφ ? 0.40 m/s Previous Answers Request Answer Submit Incorrect; Try Again; 3 attempts remaining

Answer 1

x(+) = 2+…+ 9 + finding time when x) = 0 o = P t²+ at it's at t=0 and t = -q - P Finding the time when velocity is zero de it) = apt tq It o=2ptta t=-q __ 22 at this time x(t) = P(-2) + q, la xeles en onderneming

alt) =-1.36 m Now from v=o it starts movena Fowards positive x direction 10 Houm 1036m Also at t= -as its velocity is xeЯo 1.36 m хело t = -(-1.4) = 1.944 secs 2x0. 36 Now at t isee its position is R = 0.36X1 - 1,481 -1.04 m at t=1 sec, it is moving towards telt and at t= 1.944 secs its velocity becomes Zero.

-0.32m 100 < 0.16m t=48ec t =1.9448ec t=1s Now at t = 4 sec x(4) - 0.36X16 – 1.4x4 __= 0.16___ Now , we know that average speed is equal to = total distance total time total distance travelled from t-isee to t = user is 0:32 +0.32 + 1.04 + 0.16 = 1 gum

average speed = 1.84 averag = 1.84 u-1 =484 = 0.613 m/sec 3