Question

The Hindenburg Zeppelin used 1.98 x 100 m of hydrogen to lift itself plus any payload. The density of the hydrogen can vary due variations in the pressure of the gas plus about 10% due to temperature changes. On a particular day the density of air was 1.245 and the density hydrogen was 0.09. Considering only the volume of the hydrogen and an equal volume of air, what is the maximum weight that the Hindenburg could lift, (including its own weight)?

Answer 1

Buoyant force, Fb = (V_submerged) (rho_fluid) (g)

where fluid is the air.

so Fb = (1.98 x 10^5 m^3)(1.245 kg / m^3)(g)

Fb = 2.416 x 10^6 N

for equilibrium,

F_net = Fb - Fg = 0

Fg = Fb = 2.42 x 10^6 N. .......>Ans