Question

3.2 Implementar la tabla de verdad de la función original y la simplificada, demostrar que son iguales. 3.3 Implementar los circuitos en multisim. 4. IMPLEMENTAR EN MULTISIM EL SUMADOR COMPLETO DADO POR LA SIGUIENTE TABLA DE VERDAD B COUT Σ 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 1 1 C. = acarreo de entrada. Algunas veces se designa como CI = acarreo de salida. Algunas veces se designa como CO. Σ = suma C

hello I need help with this is in Spanish but I will translate.

3.2 Implement the truth table of the original function and the simplified one demonstrate that are equal. (I belive they are talking about the table in the bottom of the picture).

3.3 It says, Implement circuits in Multisim.

Hope you can help me. Thank you.

Answer 1

Question 3.2

А B Cin COUT M 0 0 0 0 0 0 0 1 0 1 0 1 0 0 1 0 1 1 1 0 1 0 0 0 1 1 0 1 1 0 1 1 0 1 0 1 1 1 1 1

Expression for

Σ

We will write the expression by identifying the rows when the value of is ‘1’.

Σ

So

I= A.B.Cin + A.B.Con + A. B.Con + A.B.Cin

Expression for

COUT

We will write the expression by identifying the rows when the value of is ‘1’.

Cout

So

Cout = A.B.Cin + A. B. Cin + A.B.Con + A.B.Cin

For Sigma, we have wired the circuit corresponding to the original circuit in NI MULTISIM as follows

· 1 :3 5. 8: XLCI >AB .B U2A U1A 74L S04N Logic converter-XLC1 Х 74LS11N U4A Out 0 0 0 o D E F G H с 0 Conversions 74_$32N B 0 0 U1B 0 000 001 002 A 0 0 0 0 1 D 1011 04B 1 0 1 003 0 101 U2B AIB 1 1 1 0 0 1 1 74LS11N 1 101 SMP AB 744 $32N 004 005 006 007 0 0 1 0 1 1 AB 101 1 1 1 74L SO4N AB U1C SIB NAND U4C 74LS11N U2C — 74_$32N U3C 74L SO4N 74LS11N Design1

We can see that the sum or signal output is same as that in the table

For Carry OUT, we have wired the circuit corresponding to the original circuit in NI MULTISIM as follows

... 1.... . 2 4 .5 -6 .8 XLCI: A AB Logic converter-XLC1 Out 0 o .... U2A o D E F G H B U1A Conversions 0 1011 74L S04N U4A A B C 0 0 0 0 0 1 0 1 0 0 1 1 0 0 1 0 1 1 0 1 1 1 000 001 002 003 004 005 006 007 1 0 1 0 1011 A1B 74LS11N 1011 SIM AB 1 AB 1011 744 $32N 1 С U1B AB U4B AB - U2B NAND 74LS11N 74_$32N 74L $04N D U1C U4C 74LS11N U2C 744 $32N U3C F 74L S04N 74LS11N . FA Sum Original FA Carry Out Original *

We can see that the Carry OUT output is same as that in the table

Now lets minimize the expressions using Boolean Algebra

Expression for the Sum

Σ

= A. B.cin + A.B.C + A. B.C + A.B.Cin

Σ = Α.(B.C + B.C.)+ A. (Β.C. + B.C.)

Σ = Α.(BBC)+ A. (B0C)

E = A.( Bin) + A. ( BC 177

I= A B Cin

Expression for Carry Out  

COUT

Cour = A.B.Cin + A. B.Cin + A.B. Con + A.B.Cin

Cour = (A.B + A. B ). Cin + A.B.Con + Cin)

Cour = ( AB). Cin + A.B

For Sigma, we have wired the circuit corresponding to minimized expression in NI MULTISIM as follows

XLC1. Logic converter-XLC1 AB x Out 0 o o o OI 0 E F G Conversions 0 1 1 101 А B C D 0 0 0 0 0 1 0 1 0 0 1 1 10 0 1 0 1 1 1 0 1 0 000 001 002 003 004 005 006 007 1011 81B 1 B 101 SIM AB U1A 0 0 AB 101 1 1 1 AB 74LSSON AB - NAND U1B 74LSSON E FA Sum Original FA Carry Out Original * Design1*

We can see that the sum or signal output is same as that in the table

For Carry out , we have wired the circuit corresponding to minimized expression in NI MULTISIM as follows

COUT

2 3 5: -6 7 XLCI AB Logic converter-XLC1 Out O o 0 Oo IO Conversions 0 0 0 101 U1A o O A B C D E F 0 0 0 0 0 1 0 1 0 0 1 0 0 1 0 1 0 1 1 1 000 001 002 003 004 005 006 007 1 1011 AB 1 0 1 1 1 1 101 SIMPA1B AB 1011 1 74LS86N U2A AB + AB + NAND 74LSON U3A U2B 74LS32N 74LS08N FA Sum Original FA Carry Out Original * | Design1 *FA Carry Out Minimized *

We can see that the Carry OUT output is same as that in the table