Question
What is the answer for heat transferred by metal, qmetal? What is the answer for heat capacity of metal, Cmetal? Data is in the first picture.
A. Heat Capacity of a Metal Aluminum Iron Mass of metal piece Volume of water Mass of empty calorimeter cups Mass of calorimeter cups+H2O Mass of water Initial temperature of metal 3.32610.26 30.00 30.00 ml 4.943 4405 g 26.674.33 (temperature of hot H2O bath) Calculations: 30,6 6-69 3.32 1 Iron Temperature Readings, °C Initial 1 minute 2 minutes 3 minutes Aluminum 20,02 2oro 20.03 20.ol 2b.03 o ol 20.02 Add metal to water 4 minutes 21.00 2L0O 2102 5 minutes 6 minutes 7 minutes 8 minutes DO 21.02 2102 2100 Chemistry 131 : EXPERIMENT 7
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Answer #1

Alminium

Heat absorbed by H2O will be equal to Heat transferred by metal

Heat transferred by metal = 112.72 J

(m* Cp* delT)water = (m* Cmetal * delT)metal

26.674 g * 4 J/g.C * 1.01 C = 3.326 g * Cmetal * 21.02 C

Cmetal = 1.54 J/g.C

Iron

heat transfered by metal = 81.74 J

(m* Cp* delT)water = (m* Cmetal * delT)metal

19.733 g * 4 J/g.C * 0.99 C = 10.267 g * Cmetal * 21.03 C

Cmetal = 0.362 J/g.C

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