Question

Please help with the last couple of calculations on the chart and then the calculations on the bottom? Just a little confused. Thank you!!

Table 1: Specific Heat Capacity of Common Substances Substance Specific Heat Capacity H2O Ice at 0d Seam at 100°C Aluminum Chromium Lead Magnesium Manganese Tin Zinc 4.184 2.010 2.010 0.900 0.448 0.160 1.017 0.479 0.213 0.388 Table 2: Mass Water Unknown Metal Stri Mass 45.0 10.2 Table 3: Specific Heat Data Temperature (C Time Trial 1 Trial 2 Trial 3 Initial Temp Water (0 min Initial Temp Metal 1 minute 70 F 70 F 70 F 103 F 102 F 102 F 2 minutes 3 minutes 4 minute:s 5 minutes 72 F 71 F 71 F 70 F 70 F 74 F 73 F 72 F 72 F 72 F 75 F 73 F 73 F 71 F 71 F Final Temp 70 F 72 F 71 F Specific Heat Average Specific Heat of the unknown metal dT = Tfinal-Tinitial @water-Csp water × mwater × ΔTwater qmetal + qwater0 Imetal water

Answer 1

RIAL 2 /0 2 Me Me 0 72 -30 103 °C Metal waleo 2 t 455 (4184) (70-70),co

Caltulat on 72°C ·一一(As) (4,84) ( 72-70) 376. 56 J and tame fat aaa LO Mi (10.2)-(Cu) 172-102)| 376.56

wate do hat gained 45 14184) (71-70) 28 Au