Question

I need help finding the average heat capacity and the average atomic mass of the unknown metal !

Table II. Data and Calculations for Unknown Metal, Code Number of Metal 6.57g 81.429 6.979 84.203 Include units for all Trial Trial 2 Trial 3 measurements Mass of metal 88.139 88.739 88.739 Temp of boiling water (T ) (initial Tof metal) 99.98 °c 99.99€ 100°C Mass of calorimeter 6-579 Mass of calorimeter & water 8484 Initial Temp (T ) of calorimeter water 22.2°C 22.2°C 22.26 Final temp of metal & water (inside calorimeter) 38.40°C 39.01°C 39.00°C Mass of water inside calorimeter 78.959 77.639 78.279 AT of water (Tr-Tiw) 16.7°C 16.8°C 16.8°C AT of metal (Tr-Tcm) - 61.08°C -60.99°C -61.0°C *Heat gained by the water qw - mx w X ATW 5516.465 5456.715 5501.69] **Specific Heat of metal (cm) q= = m X Cm X AT 1.02T 1.025 q lost by water = -9 gained by goc 9°C metal Average specific heat capacity of unknown metal Average Atomic mass Calculate the range from the high & low values allowed by the uncertainty in the Law of Dulong & Petit. Possible identity of unknown element based on comparison with a table of actual e values. Some tables are given in calories/g °C, other tables are in joules/g °C. Use the factor 4.184 J= 1 cal to convert. Based on the information above, make a plausible prediction on the identity of the unknown metal.

Answer 1

we bave & heat capaufes on 3recadi gs 1.02 1-e 02 J I 1.01 / Average specie heat capacity o unknosn Specipc heatteothal 1+ s.h tial 2t Satia3 metal 3 1.02 +101+102 3 avaagehat 1.01e caphit gimilany we have 3 masses J/ metal 8339 88.73 3: atomic maus 28.73 +32.73 +7 .avarage 3 82739 anarage atomic maas g8.73g cacra