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Solve the following problems: (25 pts. each) Problem 1 Determine the support reactions then draw the shear and bending moment

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Answer #1

p=lik LE24 * Reactions: E EMOA=0 11416-PBX 24 =0 (RB = 7. 3k] RAT RB = 11 It shear Force : - VA= 3.686 creeft) = 3.62k 3.68kNELL 58.72kft. * Bending momenti MA - MBRO - Mc=RAXIS = 3.61x16 = 58.92 Kft. +! (B.M. Diagram) 2) Ut → Err222 A .. A as a 4.56.25k D o.Ask 4.5к (S.F. Piagram) * Bending Moments - MA=MB= 0 Mc = RAX4.5 = 6.25x4.5=28.13k.ft. mo=RAX (9+4.5) -789 = 6.25x1LAU CONTENUL * shear Forces . VA=8.92k ucceeft)=8.92 - 0.3x5 - 7.42k TVcrright ) = 7.42 -10 = -2-5rk = -2.58-0.3x10 =-5.58K.8.9215 S67.4215 5.58k 2.581 (5.F. Diagram) * Bending moment: MA= MB=0 - Mc= RAXS-0.385x5 =8.9245 -0.385x2.5 = 40.85k.it. forswa4kift. - L=81 * Reactions → EFY=o RB = 4x8 [PB = 32k ak shear Force: ~ VB -4xr -32K 32K esif. piagram) * moment : MB - 4X8*

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