Question

For the beam and loading shown in Figure A2: - a. Determine the support reactions b. Draw the shear and bending moment diagrams c. Determine the maximum absolute value of shear force and bending moment P= 100 N P= 140 N w = 30 N/m A B 4 m 7 m 10 m 3 Figure A2.

Answer 1

Given Beam: Plus Peloot (w 30 N/un RAL r 55D Rwym lx 2 am @ let Ray and Ran be vertical and Horizontal reactions at bount A. respectively. Re be the reaction at B. Now, RAH = & forces) Horizontal - TRAHED and - Ray TRB = 2 forces) vertical RAYT RBF 140+ (30 x 3) + 100 Rayt R8 = 330 es - Taking moment about A- ŹMA=0 RAKIO = 140x4 + look f Re = 175.5 f gox 5.5 and Ray 330-175 5 Por 1545N NA 154.54 SFD Convention: Taking upward positive from 114. 50 (left hand side 75.5 175.5N 1455

AM (Nm) BMDU -626491 - 5265 YO sign Convention Toking clockwise moment from left hand side- positive © As from shear Maximum shear force force diagram, It is clear that occurs between B and D. Maximum shear Ponce – 175.5 N) Maximum Bending moment occuras at point where Shear force changes its sign e shear force is zero- Here shear force is zero between cand o so taking an arbitrary section x-x- Bending moment at x-x section - Marx = 154.5x - 140 (x-4) - (x-41 x 30 for maximum or minimum- dMack=0 - 154.5-140- (x-4)x30 20 x = 4:483m so, Maximum Bending moment- (BM) Max = 154.5 K 4.483 - 140 x 14.483-4) -(ep.483-4) 430 = 692.6235 - 67.92 -3.504 -|(BMacok = 61.4995) Nm

AM (Nm) BMDU -626491 - 5265 YO sign Convention Toking clockwise moment from left hand side- positive © As from shear Maximum shear force force diagram, It is clear that occurs between B and D. Maximum shear Ponce – 175.5 N) Maximum Bending moment occuras at point where Shear force changes its sign e shear force is zero- Here shear force is zero between cand o so taking an arbitrary section x-x- Bending moment at x-x section - Marx = 154.5x - 140 (x-4) - (x-41 x 30 for maximum or minimum- dMack=0 - 154.5-140- (x-4)x30 20 x = 4:483m so, Maximum Bending moment- (BM) Max = 154.5 K 4.483 - 140 x 14.483-4) -(ep.483-4) 430 = 692.6235 - 67.92 -3.504 -|(BMacok = 61.4995) Nm

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