a) E(X) = 1 * 0.3 + 2 * 0.4 + 3 * 0.2 + 4 * 0.1 = 2.1
b) E(X2) = 1^2 * 0.3 + 2^2 * 0.4 + 3^2 * 0.2 + 4^2 * 0.1 = 5.3
V(X) = (E(X)2) - (E(X))^2
= 5.3 - (2.1)^2
= 0.89
A chemical supply company currently has in stock 100 lb of a certain chemical, which it...
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