Demand | 80 | 90 | 100 | 110 | 120 |
Probability | 0.2 | 0.15 | 0.3 | 0.25 | 0.1 |
Cost | 12 | ||||
Selling price | 16 | ||||
Unsold price | 5 | ||||
Average demand = 80X0.2 + 90X0.15 + 100X0.3 + 110X0.25 + 120X0.1 = 99 | |||||
Profit per unit | 4 |
Demand | Order qty | Qty at full price | Qty unsold | Full profit | Unsold profit | Total profit |
80 | 99 | 80 | 19 | 320 | -133 | 187 |
90 | 99 | 90 | 9 | 360 | -63 | 297 |
100 | 99 | 99 | 0 | 396 | 0 | 396 |
110 | 99 | 99 | 0 | 396 | 0 | 396 |
120 | 99 | 99 | 0 | 396 | 0 | 396 |
We have considered demand as given above with order qty in each scenario as the average expected demand of 99 calculated above
Qty at full price will be minimum of demand and order qty
Qty unsold will be (order qty - demand) if orfer qty is greater than demand
We have then calculated the full price profit as units X profit/unit
For unsold, profit = unitsX profit/unit (here we have a loss per unit of 5-12 = -7 per unit)
Total profit is then calculated by adding above two columns
Now maxiumum average profit is 187X0.2 + 297X0.15 + 396X0.3 + 396X0.25 + 396X0.1 = 339.5
Option a is the correct answer
A restaurant plans to order dessert for the next Sunday. Each dessert costs $12 to buy...