Question

Let's use the the data above for female Kestrel length. Here are the data (again), as well as the normal scores Note that we added added one more female, and that the data are sorted): Length(cm): 25.1 25.4 25.5 256 25.8 26.6 27.0 27.3 27.3 28.2 28.6 29.1 Z-scores: -1.73 -1.15 -0.81 -0.55 -0.32 -0.10 0.10 0.32 0.55 0.81 1.15 1.73 (a) Construct a 9-9 plot (normal probability plot) (b) Verify the first three normal scores (ie, calculate the first three normal scores by hand (you want to verify the three smallest normal scores, given in bold above)).

Answer 1

Page non Answer: Given; 1. Let us take the data shown belows for female kestrel length and as well as normal scores Length cm) : 25.125.4 255 256 25.8/ 26.6 27.0 27-3 27.3 23.2 -1.73 Z-Scores -1.15 -0.81 -0.55 -0.32 -0.10 0.10 0.32 0.55 0.81 Z-Scores 1.43 Continuition; length (cm):- 28:6 29.1 1.15 a) The objective is to construct a 9-9 plot i.e, normal probability - plot. let us take ; .y-axis indicates - length Com) x-aris indicates : Z-scores t (wormal score] 16 + Length (cm) 2 3 Normal Score Normal Curve plot.

... Hence, we draw a normal 1 Page nord probability plot by using given tabular . values. b) The objective is to verify the first three normal scores. for this first we consider Count; N= 12 let us calculate mean value for the given values mean =* = Ex By substituting values , we get 25.1 +25.4 +255 +25.6+25-8 +26.6 + 27.0+27.3 +27.3+ 28.2 + 28.6 +29. 12 :. 8 32105 12 À = 26.79 Then we standard ermula determine deviation as b shown below. E (x-a n- By substituting values in above equation , we get 5.1- 26.74) +(25.4 - 26.74) +(25.5 - 26.79)2 +(25-6-26.79)' +25.8-26.74 1 +(26.6 -26.74) + (27-26.79)+(27.3-26-7)+(27-3-26.77)+(28.2-2017 +28.6-26-74) +639.1- 26.74) 12-1 (8.848 + 2.588 + 8.6122) 12-1

Page no :3 To=1.350 for three normal scores, Now we determine the Z-Scores let, for 25.1 ; Normal score is z - Value - 25.1- in above equation. By substituting values Z-Value = 25.1-26.79 1.350 -1.69 1.350 z-Value for 25.13-11251 25.4. Similarly, let us calculate for Normal score will be Z-Value25-4- 25.4 -26.79 1-350 ( for 25.4 7- Value = -1.029) Finally, let us calculate for 25.5 Normal score is calculated as follows; E- Value = 25.5-2

Page no:-4 25.5 - 2.79 1.350 1.29 1.350 z-Value for 25.5=-0.955 let us shour the first three normal scores as follows: Z- Score for 25.1=-1.251, Z-score for 25.4 = -1.029, Z-score hor 25.5=-0.455.