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The current in a 60.0-mH inductor changes with time as i = 3.00t2 − 7.00t, where...

The current in a 60.0-mH inductor changes with time as i = 3.00t2 − 7.00t, where i is in amperes and t is in seconds.

(a) Find the magnitude of the induced emf at t = 1.00 s.

=_____mV

(b) Find the magnitude of the induced emf at t = 4.00 s.

=_____mV

(c) At what time is the emf zero?

=_____s

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Answer #1

V(t) = L(dI/dt)
V(t) = (60.0e-3 H)(6t - 7 s)

(a) V(1) = (60.0e-3 H)(6 - 7 s)
V(1) = -0.06 V

(b) V(4) = (60.0e-3 H)(6*4 - 7 s)
V(4) = +1.02 V

(c) 0 = (60.0e-3 H)(6t - 7 s)
0 = 6t - 7
t = 7/6 s

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