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Can you please show all work and calculations. Also can you
explain how you got the...
please show explanation! thank you Each of the electrons in the beam of a television tube...
please show explanation! thank you
Each of the electrons in the beam of a television tube has a kinetic energy of 10.0 keV. The tube is oriented so that the electrons move horizontally from north to south. The vertical component of Earth's magnetic field points down and has a magnitude of 52.0 ut. (Ignore the northward component of Earth's field.) In what direction will the electron beam deflect? O north O east O west o down O up south Submit...
The electrons in the beam of a television tube have a kinetic energy of 2.40 ×...
The electrons in the beam of a television tube have a kinetic energy of 2.40 × 10-15 J. Initially, the electrons move horizontally from west to east. The vertical component of the earth's magnetic field points down, toward the surface of the earth, and has a magnitude of 1.67 × 10-5 T. What is the acceleration of an electron due to this field component?
Your answer is partially correct. The electrons in the beam of a television tube have a...
Your answer is partially correct. The electrons in the beam of a television tube have a kinetic energy of 3.04 * 10-15 J. Initially, the electrons move horizontally from west to east. The vertical component of the earth's magnetic field points down, toward the surface of the earth, and has a magnitude of 1.65 x 10-ST. What is the acceleration of an electron due to this held component? Number 24 E14 Units m/s^2
nt FULL SCREEN PRINTER VERSION NEXT Cnapter 41, ProDiem b2 A smail compass is held horizontally,...
nt FULL SCREEN PRINTER VERSION NEXT Cnapter 41, ProDiem b2 A smail compass is held horizontally, the center of its needle a distance of 0.240 m directly north of a long wire that is perpendicular to the earth's surface. When there is no current in the wire, the compass needle points due north, which is the direction of the horizontal component of the earth's magnetic field at that location. This component is paraliel to the earth's surface. When the current...
If you can show me step-by-step, I would greatly appriciate that BACK NEXT Pool 21.1: Quito...
If you can show me step-by-step, I would greatly appriciate
that
BACK NEXT Pool 21.1: Quito is the capital city of Ecuador in South America and locate... Quito is the capital city of Ecuador in South America and located near the equator. The Earth's magnetic field near Quite is horizontal and points north the magnetic force exerted on a proton traveling near Quito is directed due east, what is the direction the proton is moving? south east west vertically downward...
The size of the magnetic force on a straight wire of length L carrying current I...
The size of the magnetic force on a straight wire of length
L carrying current I in a uniform magnetic field
with strength B is
F=ILBsin(?).
Here ? is the angle between the direction of the
current (along the wire) and the direction of the magnetic field.
Hence Bsin(?) refers to the component of the
magnetic field that is perpendicular to the wire, B?. Thus
this equation can also be written as
F=ILB?.
The direction of the magnetic force on...
Can someone please help me with D and E. Constants Part A To understand the magnetic...
Can someone please help me with D and E.
Constants Part A To understand the magnetic force on a straight current-carrying wire in a uniform magnetic field. Magnetic fields exert forces on moving charged particles, whether those charges are moving independently or are confined to a current- carrying wire. The magnetic force Fon an individual moving charged particle depends on its velocity and charge er. In the case of a current-carrying wire, many charged particles are simultaneously in motion, so...
A 2.30 m length of wire is held in an east–west direction and moves horizontally to...
A 2.30 m length of wire is held in an east–west direction and moves horizontally to the north with a speed of 14.7m/s. The vertical component of Earth's magnetic field in this region is 40.0 μT directed downward. Calculate the induced emf between the ends of the wire and determine which end is positive. magnitude mV positive end ---Select--- west end both neither east end
How large a current would a very long, straight wire have to carry so that the...
How large a current would a very long, straight wire have to carry so that the magnetic field 1.90 cm from the wire is equal to 1.00 G {comparable to the earth's northward-pointing magnetic field)? I = A If the wire is horizontal with the current running from east to west, at what locations would the magnetic field of the wire point in the same direction as the horizontal component of the earth's magnetic field? at all points directly north...
The electron that flies in the tube has energy of 12 keV. The cathode-ray tube is oriented so that the electrons move in a horizontal direction from the south to the north. Earth's magnetic field...
The electron that flies in the tube has energy of 12 keV. The cathode-ray tube is oriented so that the electrons move in a horizontal direction from the south to the north. Earth's magnetic field component B = 5.5 * 10-5T is facing downwards. In what direction will the electron beam be tilted? How big is the electron beam deflection x when the electrons in the tube have flown 20 cm?
please show explanation! thank you
Each of the electrons in the beam of a television tube has a kinetic energy of 10.0 keV. The tube is oriented so that the electrons move horizontally from north to south. The vertical component of Earth's magnetic field points down and has a magnitude of 52.0 ut. (Ignore the northward component of Earth's field.) In what direction will the electron beam deflect? O north O east O west o down O up south Submit...
Your answer is partially correct. The electrons in the beam of a television tube have a kinetic energy of 3.04 * 10-15 J. Initially, the electrons move horizontally from west to east. The vertical component of the earth's magnetic field points down, toward the surface of the earth, and has a magnitude of 1.65 x 10-ST. What is the acceleration of an electron due to this held component? Number 24 E14 Units m/s^2
nt FULL SCREEN PRINTER VERSION NEXT Cnapter 41, ProDiem b2 A smail compass is held horizontally, the center of its needle a distance of 0.240 m directly north of a long wire that is perpendicular to the earth's surface. When there is no current in the wire, the compass needle points due north, which is the direction of the horizontal component of the earth's magnetic field at that location. This component is paraliel to the earth's surface. When the current...
If you can show me step-by-step, I would greatly appriciate
that
BACK NEXT Pool 21.1: Quito is the capital city of Ecuador in South America and locate... Quito is the capital city of Ecuador in South America and located near the equator. The Earth's magnetic field near Quite is horizontal and points north the magnetic force exerted on a proton traveling near Quito is directed due east, what is the direction the proton is moving? south east west vertically downward...
The size of the magnetic force on a straight wire of length
L carrying current I in a uniform magnetic field
with strength B is
F=ILBsin(?).
Here ? is the angle between the direction of the
current (along the wire) and the direction of the magnetic field.
Hence Bsin(?) refers to the component of the
magnetic field that is perpendicular to the wire, B?. Thus
this equation can also be written as
F=ILB?.
The direction of the magnetic force on...
Can someone please help me with D and E.
Constants Part A To understand the magnetic force on a straight current-carrying wire in a uniform magnetic field. Magnetic fields exert forces on moving charged particles, whether those charges are moving independently or are confined to a current- carrying wire. The magnetic force Fon an individual moving charged particle depends on its velocity and charge er. In the case of a current-carrying wire, many charged particles are simultaneously in motion, so...
How large a current would a very long, straight wire have to carry so that the magnetic field 1.90 cm from the wire is equal to 1.00 G {comparable to the earth's northward-pointing magnetic field)? I = A If the wire is horizontal with the current running from east to west, at what locations would the magnetic field of the wire point in the same direction as the horizontal component of the earth's magnetic field? at all points directly north...
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