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ANALYSIS II 2nd Edu The transformer is ideal. Calculate the power delivered by R=40 ohms (use phasor domain). ai on W lloo :1

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vol 11oo : 100 w COS2000 Hug your W = 2000 radlsec XLEWL= 2000 x 3 x 103 = 1612 lycos 2000t = v Lo voits (taking volts) maa*12+ Ia (516) -(5)-12 740 Kul in 100 p (2 co Eva j 16 Ia 40 I +40120 + (4+31617-401, - V. Iz=111, V=IV2 2 => (40 + 16 ) I2 -V 511(400+j176) (460+11361 6 from m3 v=1+39011 Vi = 1+ 390 (1) 1+390.17 = 4400 I1 +1193474 --- 50 2,022 x16 I= 4016 +1934 -9-resistir always absorbs power power delivered to 40 si is so > = (1 - 12 ms R watt? (2.23 2.245810 2 X40 = 12.008x16-4 ~ Ool

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