Question

I am really need these solutions. Can your help me please? this is a last part for my class final. I am really stuck at it

Problem 1 If v(t) = 80 cos(200t) V and i(t) = 180 cos(200t + 75°) mA for some load, then calculate the instantaneous power and average power absorbed by the load Problem 2 Find the average power absorbed by the 102 resistor in the circuit below 492 -15.2 20/45°v 01v. 81. 59 109 {v. Problem 3 Solve for the value of load resistance R in the circuit below that will achieve maximum power transfer 1002 -11002 31000 1000 11002 Problem 4 Calculate the RMS and average values for the following periodic signals: a) 5 cos(100) V b) 2 sin(2t) + 2 A c) 5V amplitude square wave voltage signal of frequency 500Hz with -2V offset Problem 5 Find the RMS and average values for the voltage waveform shown below

Answer 1

vt)go Caf 200ty it) o (20ot+15) mA P)=vd) it) Pt-1460,8 200t as200ot1) = 14400C3(2+15-29f)+C05 Q400t+75*) 2 pt 1200 Co SC00E+ 75 =1200 0. 258 t Co 400ot os15'- yeot is"| = 1200 0.258 o3400-.q cs sin 40ot o 258 1851-6 Gs Lpoot -6948 Sin 400tw (1857.6 P nstantaneug poier 1&S7.6W Avwrage poer, Pay 4n HE o.V is -20 4s40.1 40.1 ,20 =0 KCL Lo. 178-63-4 -8i,

V,4472116.56 /o-js =40/-90 i, Omas 40.1x 40/-90 į, = 20/45* 3.53590 A -". from .S35 vC4-g0) x-515/90*) m 4412-16.50 x 3.535g0 V, 158. 08-26.56 V IL141.42 0 IL14.142A Average pouer abserbed by the vesistar given Phoa = 4-14216)1442 1999.96) W

find th using hevenins theoreun AUo hen it is vemoved 100n o0 X (loo+o0 -lo0 t Ath 00/-53.13 Rth Rth (60-8a for Marimum po LJer toasfex R Rth 6o+to R = (60jro .. RE lo0/53.13n Ca 5a3ot v )s a ot 5 3.535 V VTW ax 5 Vavg t) = (2+ 2 2tJA Iavy 3.18 3 V (b) = 2 A 2.449 A

otsec d)2t 1zt2 sec 4V 2 1-4x(2- Vavy + +2 2 육 Jx낚 .(Vm=3- S59V +8x -1)