Question

a mordant is a substance that combines with a dye to produce a stable fixed color in a dyed fabric. Calcium acetate is used as a mordant. It is prepared by the reaction of acetic acid with calcium hydroxide

2CH3CO12H+CA(OH)2 >Ca (CH3CO2)2 +2H2O

what mass of Ca(OH)2 is required with the acetic acid in 25.0ml of a solution having a density of 1.065g/ml and containing 58.0%acetic acid by mass

Answer 1

Solution :

Soluring First we will Calculate the moss of solution Moss of solution = Density & volume = 1.0652x25ml > 26.625 g Now we have to Calculate the mass of Accric acid As we are given that 58% Alelic acid by moss That means 58gm of accric acid present in loogn of solution As loog of solution contain 58gn of Alefic acid . So 26.625g of solution contains 261625 458 = 15.44g of achcacid Now we have to calculate the moles of acetic acid So mu 4 ch, Cooh2 мм с насоон moby mons of Chycoon 60 g/mon moles Now we have to calculate moles of Ca(OH)2 2 CH3CO2H + Caron) CacC113 CO2)2 + 2H20 From the reaction we conclude that н ь то4 4 Cng Cooи та еф wiImo Ca(он), so 0.257 more of crez coon React with anse 0.257 2 01258 more of 15.498 ) 0257 2 0-25 o Caoni

Now, we have to Calculate the man of calon Man of CaCOH)2 = aroles of cacola x moles mon of 20.1258 mole x 742 Caloni mole » 9.3099m) and

Therefore, the mass of required is 9.3092 grams

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