Homework Answers
Mass of two nitrogen atoms = 14×2 = 28 g
(Atomic mass of N is 14g)
Molar mass of compound = 28 + 16n
(n is number of oxygen atoms)
So, Percent of nitrogen = 28×100/(28+16n) = 25.94
(28+16n) = 2800/25.94
28+16n = 107.94
16n = 107.94-28
n = 79.94/16 = 5
So, 5 oxygen atoms are present in second compound.
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