Adam Ant gets a running start and leaps with speed 390 cm/s and lands on top...

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Question

Answer 1

Answer #1

Conserving energy,

1/2 * m * v2 = 1/2 * m * v2 + m*g*h

or, 1/2 * 3. 9* 3.9 = 1/2 * v^2 + 9.81 * 0.23

Hence, v = 3.27 m/s = 327 cm/s

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Answer 2

Answer #2

Lets supose that the ant jumps verticaly then, the vertical velocity variates with the height as:

v_y^2 =v_y_0^2-2gh ,

substituting the values:

$v_y =\sqrt{(390 ~cm/s)^2-2(980 ~cm/s^2)(23 ~cm)} = 327.14 ~m/s$

The answer is d.

Answer 3

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