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(1) Suppose that X is a continuous random variable with probability density function 0<x< 1 f() = (3-X)/4 i<< <3 10 otherwise

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[Page 1 x is a continuous random variable with probability density function f(x) = (x ocXLI ) (3-X) 1<x<3 otherwise E(X) = Sxpage 2 - 1.1666 mean - €) 1.1666 How, V(X) = E(X) - (E(x))? 00) dx • f(x) dx Ex) = 2x² f(x) dx Sztcx) dx Sezort for xdr + (3(page 3 = 0.25 +1.6875-0.1875 = 1.75 E Cx²) = 1.75 By using formula, V(X) = E(X?) - [EO] = 1.75- (1.8666) 2 = 0.3889 V(x) = 0(page 4 312 * yadx+502) - (1 - 0) + (1 - 2 ) - ( 2 1 - 1)] = 1 + 0.84375 -0.625 = 0.71875 [ P ( x < 2 ) = 0.71875 © Also, wepage 5 x dx = 0.25 -0.25 = 0.7071 The first quartile is 0.7071

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