Homework Answers
Answer #1
Applying KVL to loop 1, 2, 3 1 implies - 28 + I_1. 1 + 4 (I_1- I_2) + 12 + 1 (I_1- I_3) = 0 6I_1 - 4I_2 - I_3 = 16 2 implies 2i_2 + 2 (i_2- I_3) + 4 (i_2 - I_1) = 0 - 4i_1 + 8i_2 - 2i_3 = 0 3 implies I_3 = 8 A 1 (8 - I_1) - 12 + 2 (8 - I_2) = 0 8 - I_1 - 12 + 16 - 2I_2 = 0 I_1 + 2 I_2 = 12: 4 from 1 implies 6I_1 - 4I_2 - 8 = 16 6I_1 - 4I_2 = 24 implies 5 solving 4 &5 we get I_1 = -6, I_2 = -3, I_3 8A V_s implies Apply KVL implies V_s + 1 (I_3 - I_1) - 12 + 2 (I_3 - I_2) = 0 V_s + (8
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