Question

ve NODE-VOLTAGE METHOD TO FIND V W 16.30 the answer is. a)160v. b) 28.240 C) 16V d) 48 €)9.41V SA 23ze Szov FIG.3 Du asz 2.USE NODE-VOLTAGE METHOD TO CALCULATE A{Bold)infig. 4 The answer is: on her 9.)+747.42W b)-74742WC)+50W d+960We)90w 381 611052 301, -------------------... AG.4 49.4 L IAR... 3.456. Mesk. Cult METHOD TO FIND P(BA) Caller toonhce ... in 16.5. The answer is . ... a)-819.12W b).1748,03W 4-746.08W 1. d) +819.12W e) NONE OF THE ABOVE 300V 4202 rosy lor . 16.5 L 4. USE MESH-CONENT METHOD TO FIND P (204.) in Shaba The answer is a a) +200w b)-200w C)=740W ver var d) +3bow ) NONE OF THE ABOVE 20V 6A gor FIG. 6

Answer 1

gicen CrCuit s Yi Sef- Aply alodal Analyss et xlede vi. 5-0+-20 32 246 VithV,-&v 160 = 240 ophion O T=48 volt giren Cr Cuit is Apply Alod al Andtya's at Alode V, - 301x V,- O 8 2-' col;-3807 V,+2y -Goix =0 to - 13, -Go k=360 from cir Cut, =-V =) 10ix =-1 -) +4 +oia=0

; = -2 A. V= 201elt Apply krL in loepO ;= 3I +30xI > 20 = SIt 30(-2) L: PC3012) = 30i. I -- 30x(-2)· I6 -960 lalatl @ -960datt given Cisaut int ఇం 3oov letus Consider facee boog ৪ A and then respecti're Cullauti ase Coops I Iz & Is Med Arclyein@I , 300 = 5I, +20 CIst Iz)+7(I,I3) =) 32I,+2OI2+7I3= 300 Mesh Andyn's @Iz =) 20I, 125I2-I -

bom loop®, Is=8 (3 Gelueng equationg I」に485A ;z= Gl4 4A Iー8A @&(3) Apply kvLin loop Is l.CI3-Jz)+7CI HI;)=\" =) Cs - 4.44)+7c4.85)=V V. 8=93151x8 = 748.08WettL PCSA)= %3D FThion B que given Circuit is let us Connidler troo loops and tee sefectve leop In Culleuti acé I,& Iz. from Loop ORO Ir I, =6-0 Apply supostaesh Analyni's inleop@«® 20 = 4I,+9I2-90+6I,+1.I, SIstis I, =llo - saldy equations © ゴニ1OAン Iyニ P(2o) = 2O X 10 = 200 LlattL option ©