2. Suppose you have the following null and alternative hypotheses: H: os 34.5 HA: 0 >...
Suppose you have the following null and alternative hypotheses: HOS 28 HI 28 it is known that the standard deviation is 401 You take a random sample of 15 bevations and find that the sample means 30 What is the most accurate and that you can make about the p-value for this test? D-value 0.04 D-value < 0.07 D-value < 0.01 p-value < 0.025 p-value < 0.10
Consider the following hypotheses: Check my work Ho! HS 570 HA: > 570 Find the p-value for this test based on the following sample information. (You may find it useful to reference the appropriate table: z table or table) a. I = 576; s = 21; n = 27 0.01 s p-value < 0.025 0.025 s p-value < 0.05 Op-value 20.10 p-value <0.01 0.05 s p-value <0.10 b. x=576; s = 21; n = 54 p-value < 0.01 0.01 s...
Consider the following hypotheses: HO: > 220 HA: U <220 A sample of 72 observations results in a sample mean of 209. The population standard deviation is known to be 18. (You may find it useful to reference the appropriate table: z table or t table) a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test...
Consider the following hypotheses: H0: μ ≤ 420 HA: μ > 420 Find the p-value for this test based on the following sample information. (You may find it useful to reference the appropriate table: z table or t table) a. x¯ = 430; s = 41; n = 13 p-value 0.10 0.05 p-value < 0.10 0.025 p-value < 0.05 0.01 p-value < 0.025 p-value < 0.01 b. x¯ = 430; s = 41; n = 26 0.025 p-value < 0.05...
Consider the following hypotheses: H0: μ ≤ 210 HA: μ > 210 Find the p-value for this test based on the following sample information. (You may find it useful to reference the appropriate table: z table or t table) a. x⎯⎯x¯ = 216; s = 26; n = 40 p-value < 0.01 0.01 ≤ p-value < 0.025 0.025 ≤ p-value < 0.05 0.05 ≤ p-value < 0.10 p-value ≥ 0.10 b. x⎯⎯x¯ = 216; s = 26; n = 80...
Consider the following hypotheses: Ho: μ s 57.1 HA: μ > 57.1 A sample of 22 observations yields a sample mean of 58.2. Assume that the sample is drawn from a normal population with a population standard deviation of 3.6. (You may find it useful to reference the appropriate table: z table or t table) a-1. Find the p-value. pvalue 20.10 Op-value0.01 0.01 s p-value<0.025 0.025 s p-value 0.05 0.05 s p-value<0.10 a-2. what is the conclusion if α-010? O...
Consider the following competing hypotheses: H0: ρxy ≥ 0 HA: ρxy < 0 The sample consists of 34 observations and the sample correlation coefficient is –0.39. Use Table 2. a. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test statistic b. Approximate the p-value. 0.01 < p-value < 0.025 p-value < 0.005 0.05 < p-value <...
Consider the following hypotheses: Ho: μ 12.6 HA: μ> 12.6 A sample of 25 observations yields a sample mean of 13.4. Assume that the sample is drawn from a normal population with a population standard deviation of 3.2. (You may find it useful to reference the appropriate table: z table or t table a-1. Find the p-value. p-value < 0.01 0.01 s p-value0.025 0.025 s 0.025 s p-value< 0.05 O.05 s p-value<0.10 。p-value 20.10 a-2 what is the conclusion if...
Consider the following hypotheses: Ho: 4 = 150 HA: H < 150 A sample of 80 observations results in a sample mean of 144. The population standard deviation is known to be 28. (You may find it useful to reference the appropriate table: z table or t table) a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal...
The null and alternative hypotheses are: H H :Hd < 0 :Hd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month: Day Day shift Afternoon shift 1 10 8 2 12 9 3 15 12 4 11 15 At the 0.05 significance level, can we conclude there are more defects produced on the Afternoon shift? a. State the decision rule....