Question

8 Suppose the following declarations and statement are in effect. What are the values of x and y in each case? *p *q; = (b) int x = 1, y = 3, *m = &x, *n = &у; *n = 5; *a += 2; (8)Please solve written in details. (4)Notice the semi colon and explain. PLEASE NO CODING(both) 4 Determine the output produced by each of the following statements: (a) for (i = 6; 1 > 0;-1) print (-") (b) for (i 0;! >= -6; --1); =

Answer 1

QUESTION (8)  

(a) x=12 and y=12

*p and *q are declare as pointer type so *p=&x means *p holds the address of x and *q=&y means *q holds the address of the y so *p=*q means assign the value of *q into *p so *p hold the value 12 , *p and x both are point the same memory location and *p as pointer type so changes in *p is parmanently so value of x also will be change

(b) x=2 and y=5

*m and *n are declare as pointer type so *m=&x means *m holds the address of x and *n=&y means *n holds the address of the y so *m=*n means assign the value of *n into *m so *m hold the value 3 , *m and x both are point the same memory location and *m as pointer type so changes in *m is parmanently so value of x also will be change so final value of *m will be 2 and *n will be 5 so x and y also hold 2 and 5

(c) x=8 and y=5

*a and *b are declare as pointer type so *a=&x means *a holds the address of x and *b=&y means *b holds the address of the y so *a=*b means assign the value of *b into *a so *b hold the value 6 , *a and x both are point the same memory location and *a as pointer type so changes in *a is parmanently so value of x also will be change so final value of *a will be 8 after 2 add in *a, and *b will be 5 after 1 decrement so x and y also hold 8 and 5

QUESTION (4):

(a) OUTPUT : ------

in this statement for loop exicute six time so six time print "-"