Question

Question Completion Status: QUESTION 5 In the diagram below, a coil of wire with a radius of 5.00 cm is in a 1.50 T magnetic field (that points into the page/screen). How quickly must the loop be removed from the magnetic field in order to produce an emf of 0.50 V? If the magnetic field is into the page. then what is the direction of the induced current in the loop? x x x x O-O T TTT # Paragraph Arial 3 (12pt) VEE %DO TT, $x Mashups I u © Ota * **** HTHLOSS Save All Answers Det a WC

Answer 1

Step 1

We have ,

E(emf) = 0.5 V

B( magnetic field density) = 1.5T

Radius of coil r = 5cm

Length of the coil = 2 *pie * r = 0.314 m

Step 2

An emf is  induced by the motion of the conductor across the magnetic field is a known motional electromotive force.

The equation is given by :-

E = - vLB

Here negative sign is just showing the phase opposition and symbols have their usual meaning as defined.

Step 3

On substitution of values what we get is,

V = E/LB

Therefore v = 1.0615711253 m s-^1

Step 4

As the the direction of main magnetic field is showing down the page or into the page so that in our coil due to its motion an emf will be generated which induce a current in the anticlockwise direction and that current creates the magnetic field of coil which suppresses the main field flux.