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An industrial engineer concerned with service at a large medical clinic recorded the duration of time...

An industrial engineer concerned with service at a large medical clinic recorded the duration of time from the time a patient called until a doctor or nurse returned the call. A sample of size 180 calls had a mean of 1.65 hours and a standard deviation of 0.82.

a) Obtain a 95% confidence interval for the population mean of time to return a call.

b) Does μ lie in your interval obtained in part (a)? Explain.

c) Perform a test (using critical value approach) with the intention of establishing that the mean time to return a call is greater than 1.5 hours. Use α = 0.05. Also confirm your decision using p-value approach.

d) In light of your conclusion in part (a), what error could you have made? Explain in the context of this problem.

e) In a long series of repeated experiments, with new random samples collected for each experiment, what proportion of the resulting tests would reject the null hypothesis if it prevailed? Explain your reasoning

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Answer #1

Given the sample size n = 180 and sample mean = 1.65, sample standard deviation s = 0.82
The (1 - alpha) 100% two sided confidence interval for population mean based on the sample data is
a) The 95% CI is
b) If population mean is mu = 1.5, it does not lie in the above interval.
c)The hypotheses are
The test statistic is
The critical value for this right tailed test is Z1-a = 1.644854
Since the test statistic is greater than critical value is
Reject the null hypothesis. That is the mean time to return a call is greater than 1.5 hours

Given the sample size n = 180 and sample mean X = 1 .65, sample standard deviation s 0.82 1-0 ) 100% two sided confidence interval for population mean based on the sample data is The 0.05,21-a/2 0.82 = 1.96 = a)The 95% CI is (a 1.65 + 1.96180 (1.530206,1.769794) b) If population mean is μ c)The hypotheses are 1.5, t does not lie in the above interval. H0 : μ-1.5 The test statistic is 1.65-1.5 0.82 180 z= 2.454221 value for this right tailed test is Z1-1.644854 Since the test statistic is greater than critical value is Z1-a-1.644854 < 2.454 Reject the null hypothesis. That is the mean tlme to return a call Is greater than 1.5 hours The P-value is P-value = P (Z > 2.454221) P-value1- (2.454221) P-value = 0.0071 < α 0.05

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