(1 point) Evaluate the double integral || 6xydA, where D is the triangular region with vertices...
Evaluate the double integral I = Slo xy dA where D is the triangular region with vertices (0,0), (1,0), (0,6).
(1 point) Evaluate the double integral / = - SD xy A where D is the triangular region with vertices (0,0), (4,0), (0,5).
Q) Calculate ;) SS the value of the double integral triangular region with vertices (0,0), (1, 1) and (0,1)) 16. 1} dA 5 & 1 + x2 ;;;) SlxdA ; R R x=8- y² I quadrant between the circles' x² + y² = 1 and x² + y²=2 circles}
6. Use the additivity of the double integral to evaluate the double integral of f(x,y) = x2-y2 over the region that is a disk x2 + y2 < 4 with a triangular hole with vertices (0,0), (0,1), and (1,1).
10. Consider the triangular region R with vertices (0.0) (a) (4 points) Sketch the triangular region R. Vertices (0.0), (0,2), and (4,0) 3/ lebel up, but do not evaluate, an integral for the volume of the solid obtained by rotating the triangular region R abo al (c) (4 points) Set up, but do not evaluate, an integral for the volume of the described solid. The base is the triangular region R. The cross-sections perpendicular to the r-axis are semi-circles with...
Evaluate the given double integral by changing it to an iterated integral. xy dA; S is the triangular region with vertices (0,0), (10,0), and (0,7) O 35 12 0 1225 6 245 12 175 6
(b) Evaluate the double integral e(y-2)/(y+2) dA where D is the triangle with vertices (0,0), (2,0) and (0,2). (Hint: Change variables, let u = y - x and v = y + x.)
NAME I.D.: 8. Evaluate the double integral where D is the square with vertices (0.2), (1.1), (2.2) and
1. An iterated double integral that is equivalent to *** dx + ry dy JOR 3. Use Groen's Theorem to set up an iterated double integral equal to the line integral $+eva) dx +(2+ + cow y) dy where is the boundary of the region enclosed by the parabolas y rand 1 = y2 with positive orientation. This yields: A. where R is the triangular region with vertices (0,0),(1,0) and (0,1) is: A B. B. So ['(2-z) dr de SL...
Use a change of variables to evaluate the double integral below, where D is the region bounded by the four lines y − x=0 y − x = 5 y + x = 2, and y + x = 4: