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6. (10 points) Let A, B, and C be sets. Prove (AuB)C(AnC) u(BnC)

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Answer #1

Proof: (A U B)∩C =(A∩C) U (B∩C)

Mathematics we use the following symbols:

U = OR = V

∩ = AND = ∧

The law state that taking intersection of a set to union of two other set is the same as taking the intersection of orginal set and both two sets separately and then taking union of the result.

let x \varepsilon (AUB)∩C , if x  \varepsilon (AUB)∩C then x is either in A or in(B and C).

x \varepsilon (A orB ) and  x \varepsilon C

{x \varepsilon A or x \varepsilonB} and x \varepsilon C

{x \varepsilon A and x \varepsilon C} or { x \varepsilonB and x \varepsilon C}

x \varepsilon (A and C) or x \varepsilon (B and C)

x \varepsilon (A∩C)U(B∩C)

therefore,

(A U B)∩C ⊂ (A∩C) U (B∩C) .............1

let x \varepsilon (A∩C)U(B∩C) , if x \varepsilon (A∩C)U(B∩C) then x is in (A and B) or x is in (B and C).

x \varepsilon (A and C) or x \varepsilon (B and C)

{x \varepsilon A and  x \varepsilonC} or {x \varepsilon B and x \varepsilonC}

{x \varepsilon A or x \varepsilonB} and x \varepsilonC

{ x \varepsilon(AUB)} ∩ x \varepsilonC

x \varepsilon (AUB)∩C

therrfore (A∩C)U(B∩C)  ⊂ (A U B)∩C ...........2

from equation 1 and 2

(A U B)∩C =(A∩C) U (B∩C)

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Answer #1

Proof: (A U B)∩C =(A∩C) U (B∩C)

Mathematics we use the following symbols:

U = OR = V

∩ = AND = ∧

The law state that taking intersection of a set to union of two other set is the same as taking the intersection of orginal set and both two sets separately and then taking union of the result.

let x \varepsilon (AUB)∩C , if x  \varepsilon (AUB)∩C then x is either in A or in(B and C).

x \varepsilon (A orB ) and  x \varepsilon C

{x \varepsilon A or x \varepsilonB} and x \varepsilon C

{x \varepsilon A and x \varepsilon C} or { x \varepsilonB and x \varepsilon C}

x \varepsilon (A and C) or x \varepsilon (B and C)

x \varepsilon (A∩C)U(B∩C)

therefore,

(A U B)∩C ⊂ (A∩C) U (B∩C) .............1

let x \varepsilon (A∩C)U(B∩C) , if x \varepsilon (A∩C)U(B∩C) then x is in (A and B) or x is in (B and C).

x \varepsilon (A and C) or x \varepsilon (B and C)

{x \varepsilon A and  x \varepsilonC} or {x \varepsilon B and x \varepsilonC}

{x \varepsilon A or x \varepsilonB} and x \varepsilonC

{ x \varepsilon(AUB)} ∩ x \varepsilonC

x \varepsilon (AUB)∩C

therrfore (A∩C)U(B∩C)  ⊂ (A U B)∩C ...........2

from equation 1 and 2

(A U B)∩C =(A∩C) U (B∩C)

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Answer #1

Proof: (A U B)∩C =(A∩C) U (B∩C)

Mathematics we use the following symbols:

U = OR = V

∩ = AND = ∧

The law state that taking intersection of a set to union of two other set is the same as taking the intersection of orginal set and both two sets separately and then taking union of the result.

let x \varepsilon (AUB)∩C , if x  \varepsilon (AUB)∩C then x is either in A or in(B and C).

x \varepsilon (A orB ) and  x \varepsilon C

{x \varepsilon A or x \varepsilonB} and x \varepsilon C

{x \varepsilon A and x \varepsilon C} or { x \varepsilonB and x \varepsilon C}

x \varepsilon (A and C) or x \varepsilon (B and C)

x \varepsilon (A∩C)U(B∩C)

therefore,

(A U B)∩C ⊂ (A∩C) U (B∩C) .............1

let x \varepsilon (A∩C)U(B∩C) , if x \varepsilon (A∩C)U(B∩C) then x is in (A and B) or x is in (B and C).

x \varepsilon (A and C) or x \varepsilon (B and C)

{x \varepsilon A and  x \varepsilonC} or {x \varepsilon B and x \varepsilonC}

{x \varepsilon A or x \varepsilonB} and x \varepsilonC

{ x \varepsilon(AUB)} ∩ x \varepsilonC

x \varepsilon (AUB)∩C

therrfore (A∩C)U(B∩C)  ⊂ (A U B)∩C ...........2

from equation 1 and 2

(A U B)∩C =(A∩C) U (B∩C)

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6. (10 points) Let A, B, and C be sets. Prove (AuB)C(AnC) u(BnC)
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