Question

Q1) A study using two random samples of 35 people each found that the average amount of time those in the age group of 26-35 years spent per week on leisure activities was 39.6 hours, and those in the age group of 46-55 years spent 35,4 hours. Assume that the population standard deviation for those in the first age group found by previous studies is 6.3 hours, and the population standard deviation of those in the second group found by previous studies was 5.8 hours. At = 5%, can it be concluded that there is a significant difference in the average times each group spends on leisure activities? Also, find the p-value. Q2) Find the 95% confidence interval for the difference between the means in Q1 above
how to solve it

Answer 1

for further any queries please comment and thank you

He is, = 2 n2=35 Ha: M. & Given, n. 35 * 99.6 &- 6.3 x - 35.4 a -0.05 Test statistics. (8 - x) 39.6 35.4 = 2.9 P-value = P(121>2.9) = 0.004 Since - value < a 0.05. > - 95% Reject There is C.I. for Ho a significant difference in the averages. 0 the sittenance of to means 39.6-35.4 1.96x6.3 35 3 35 39.6-35.4 1.96*. = ( 1.36, 7.04).