Question

A snorkeler takes a syringe filled with 16 mL of air from the surface, where the pressure is 1.0 atm, to an unknown depth. The volume of the air in the syringe at this depth is 7.5 mL. What is the pressure at this depth? If the pressure increases by 1 atm for every additional 10 m of depth, how deep is the snorkeler?

Answer 1

Using the Boyle's law we get

P1V1 = P2V2
16(1) = P2(7.5)
P2 = 2.133 atm

Let x be the depth of the snorkeler we get

2.133 = 1 + 0.1x

1.133 = 0.1x

x = 11.33m