Work Function E = 2.2 eV, Vp = 12.6 volts, λ =270 nm
Using Photoelectric effect, K.E = (hc/λ) - W
It is evident that current flows as long as electrons are moving, i.e KE>0 => (hc/λ) > W
Maximum Kinetic Energy = (hc/λ) - W
= [ (1.2398*10^-6) / (270*10^-9) ] - 2.2 eV
= 4.59 eV - 2.2 eV
= 2.39 eV
So clearly stopping potential = KE max / -e = -2.39 V = - 2.4 V
It is very much evident that Vp > -2.4 volts, current will cease
So option (A) is correct -2.4 volts < Vp
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