Question

The figures show the PV (pressure versus volume) graphs of two processes represented by straight lines The area under the curve equals the work. If volume Vinceases (V > V:) in a process, work W is positive. If volume V deceases (V <V) in a process, work W is negative. Case 1: In the left figure, pressure PA = 4.60 X 106 Pa. pressure P. = 14.72x 106 Pa. Volume VA = 0.0016 m, VA = 0.0048 m3. Don't use scientific notations in your answers. Calculate the work done from A to B. Include a proper sign. Keep 2 decimal places. This work is done by the ideal gas to the outside (Wout). Enter a number Submit (5 attempts remaining) Calculate the work done from B to A. Include a proper sign. Keep 2 decimal places. This work is done ON the ideal gas (Win) by the outside. Enter a number

Answer 1

Let us take a point c on the line such that it's coordinate is C (V, p). Now since the clove u 1 Straight line let us find the V Equation of it P-PB = P₂ - PA (V-VB) putting the values VB-VA PB = 14.72 X 166 Pa PA = 4.60x10 Po VA = 0.0016m3 VB = 0.0048 m3 P-14.72 8106 - (14.72-4.6) x 100 (v -0.0048) 10.6048 -0.0016) on

P = 3162.5×10 v - 3162.5x 100 x 0.0048 + 1472 X10 P = 3162.5 x 10 V - 0.46x100 done V w = Pave the wark from A 0.0049 5xlov - 0.46X10 0.0016 = 3162.5 xo | Tood - 6:46 xlo®[o.cou8-0-0016] = 0.032384 " - 0.001472 X 108 = 0.030912x19 J W +3.0912 x 104 J since VB) VA Now from Blo. A the amount of work is same but tnl sign is negative since VBS VA Tw = - 3.0412 x 10 h 5 case 2 assume at any point on straight line Pressure is p and valume į v to P = mutc ey=mx+c At point is 14.52X100 = mx0.0020 + - (1)

A point o 4.40x100 = mxo.0060 + -21 on psing (4) - 24h (2) 10.12 X 10 = -0.0048 m m=- 2530x106 Palme purting this value in earn 4.4x108 = - 2530x0.006x100 + c C = 19.58x106 P = - 2530 x 108 + 19.58×108 work done to w por (-2530x100 V + 19.58x168) av Ve -2530x10 ©?? PO + 1958X10€(0.006-0-002) = – 0.04048X108 +0.07832 x 100 w = 3.784 x 1045 ge in internal energy prometoo SU= 3 (Poto - Povo) - 3 (4.4 x106X0-006 – 14.52 x 106 x0º002) AU = -3.96 X 10 J From first Law of thermodynamis. do = duelpar = 3.415x1045 19 = 3.415 x 10 4 5 1 = 2221221