A large weather balloon whose mass is 222 kg is filled with helium gas until its volume is 322 m3. Assume the density of air is 1.20 kg/m3 and the density of helium is 0.179 kg/m3.
(a) Calculate the buoyant force acting on the balloon.
3786.72 N
(b) Find the net force on the balloon.
N upward
(c) What additional mass can the balloon support in equilibrium?
kg
Please help!
here mb = 222 kg V = 322 m3 pa = 1.20 Kg / m3 ph = 0.179 Kg / m3
as we know that the buoyant force
Fb = pagV = 3786.72 N
(b) net force on the balloon
Fnet = (pa - ph)gV - mg
= (1.20 - 0.179) x 9.81 x 322 - 222 x 9.81
= 1047.335 N Ans
(c) for the equilibrium condition
Fbuoyant = Fgravitational
3786.72 = mb g
mb = 3786.72 / 9.81
= 386.006 Kg Ans
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