A ball player catches a ball 3.79 s after throwing it vertically upward.
Part A With what speed did he throw it?
Part B What height did it reach?
total time of flight , t = 3.79 s
part A)
speed of the ball = g * t/2
speed of the ball = 9.8 * 3.79/2
speed of the ball = 18.6 m/s
the speed of the ball is 18.6 m/s
part B)
mximum height reached = initial speed^2/(2g)
mximum height reached = 18.6^2/(2 * 9.8)
mximum height reached = 17.6 m
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