Question

The retinal molecule has 12 electrons that are free to move about the chain. For reasons that you may learn later, these 12 electons fill the first 6 states of the box (with 2 electrons in each state). (Figure 1) Thus, the lowest energy photon that can be absorbed by this molecule would be the one that moves an electron from the 6th state to the 7th. Use the equation that you found in Part A to determine the wavelength lambda (?) of this photon. Use the length of the retinal molecule given in the introduction as the length of the box and use m=9.11�10?31kg for the mass of the electron.

$\lambda = 4mcL^2/(2n+1)\pi (h/2\pi ))$

L = 1.5 * 10^-9

Answer 1

Given wavelength of light that must be absorbed when an electron umps from n to (n+1) Weneed to find the wavelength absorbed in order to make a transition from n-6 to n+1-7 Plugging in all the values to get 4x91x(3x10)x(15x10 (2x6+1)x3146626x10-4 5.704x10-7 m -34、 6.28 λ 1570.4 nm