We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
Find y as a function of t if 4y" – 32y' = 0, y(0) = 6, y'0) = 9. y = _______
(1 point) Find y as a function of tif y" - 16y=0, y(0) = 5, y(1) = 6. s(t) = Remark. The initial conditions involve values at two points
solve: y'''-2y''-16y'+32y=0 y(0)= 2, y'(0) = -2 , y''(0)=68
Find the impulse response function. y" +8y' + 16y = g(t)
(16 points) Find y as a function of a if y" + 16y' = 0, y(0) = -7, y(0) = 12, 7(0) = 48. y(x) =
find y(t) solution of the ivp: y''+8y'+20y=-4£(t-2),y(0)=0,y'(0)=1 where £ is the S shaped character show work
(1 point) Find y as a function of t if 121y" + 22y' + y = 0, y'(0) = 7. y(0) = 9, y =
having trouble finding y(t) NOT Correct (1 point) Consider the initial value problem y"+16y 48t, y(0)3, /(0)-9. a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). (s 2Y(s)-3s-9)+16Y(s) help (formulas) 48/s 2 b. Solve your equation for Y(s). C{y(t))=48/(s 2(s2+ 16)...
(1 point) Find y as a function of t if y" – 107 +9y = 0, y(0) = 4, y(1) = 3. y(t) = Remark: The initial conditions involve values at two points.
(1 point) Find a particular solution to y' + 16y = 40 sin(4t). yp =