Question

9.45 For the differential amplifier of Fig. 9.14, let Vcc = +5 V and IRC = 4 V. Find the differential gain Ag. Sketch and cle
- RE vojia li VCI ic over + VB2 Figure 9.14 The basic BJT differential-pair configuration.
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Answer #1

Given Vec= 5V so The=4V 126 186 DB, = +0.005sihlut) sinut VB2 = ln 0.005 ; Ad Q, , Qiz ane on. Siti = ļ VB, VB, IV. Because sAd= Vezo Vc, Vc, = 3-0.4 sinut Vb 2.vbi Vez= 3+ 0.4 sinut 1 - sm Re Ve = Vegaver [ Ad = 160 vlu] Ve=0.8 sinut 2.6 - wt ,, - 2

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