A missile of mass 1.05 102 kg is fired from a plane of mass 4.60 103 kg initially moving at a speed of 2.95 102 m/s. If the speed of the missile relative to the plane is 1.16 103 m/s, what is the final velocity of the plane?
by conservation of momentum
initial momentum = final momentum
let the final velocity of plane be v then,
(1.05 * 10^2 + 4.6 * 10^3) * 2.95 * 10^2 = 1.05 * 10^2 * (v + 1.16 * 10^3) + 4.6 * 10^3 * v
v = 269.113 m/s
final velocity of plane = 269.113 m/s
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