Question

0.8 m Question No. 4 (5 Marks) The scoop C of the front-end loader is supported by two identical arms. One of these arms (ABC) is shown in the figure. The arm is supported by a pin at (A) and hydraulic jack BD. If the sum of all forces applied on both arms is F = 3.2 kN and the hydraulic jack DB is horizontal. Determine the axial force in the hydraulic Jack BD and the magnitude of the reaction at (A). D 0.2 m

Answer 1

I have solved the question based on the concepts of mechanics and hence calculated the reaction at joint bA and the axial force action in the hydraulic jack.

Refer photographs for detailed analysis.
A RAX 1 Sountion" The resultent force acting Vertical force- RAY on B is a F: 3.2 km 0.8m Rox -f 3.2krrim 1 and a ndom ent Fx1= 3.2 korim of Im Ź Moments about - B FO: RA2X0.8 + Ray x1 +3.2=0 and from equilibrium equation {fyzo Ray = 3.2 km we get [Raya .. from Equalicom I!- Rara X 0.8 + 3.2 x 1 + 3.2 o a. Rax 2x 3.2 8kr of (a =RA2) Equation & Rox From Equilibrium ({Fx=0) Roxa Rax (-8 kN)= 8km ()

Final Free body Dragram 1 3-2 KN & KN А. 1. Axial force hydraulic Jack - 8kw (Ama) 3.2 KN & KN 3.2kor 2. Reactions at A (Am) Raa= 8ker (4) Ray - 3.2 kr (1) RÅR + Ray RA= 1) 8.66 kr (Am)
Thank you.