Question

QUESTION 1 Questions 1 through 4 refer to the following: Irmitable bowel syndrome (IBS) is a nonspecific intestinal disorder characterized by abdominal pain and iegular bowel habits. Each person in a random sample of 24 patients having periodic attacks of IBS was randomly assigned to one of three treatment groups, A, B, and C. The number of hours of relief while on therapy is recorded for each patient in the table below. Treatment 11.6 12.5 10.6 11.6 13.9 S.6 139 19.1 3.35 14.4486 11.2 23.1 8.0 12.1 13.0 13.3 11.0 15.2 15.9 14.1875 16.9270 10.9 12.3 sample mean sample variance 15.0 10.5625 5.4913 Give the value of the analysis of variance test statistic used to test H0: μΑ-μΒ μ QUES TION 2 What's the critical value the.10 significance level is used? QUESTION 3 What's the p-value? QUESTION 4 the 05 significance level? What's the decision using O Reject Ho O Dont Reject Ho Reject HA O Dont Reject HA

Answer 1

The null hypothesis is

$H0:\mu_{A}=\mu_{B}=\mu _{C}$

By using excel we can solve this question easily.

First, enter all data into excel.

Click on Data -------> Data Analysis--------> Anova: Single-Factor-----> Input Data -------> Select all data -------> Output Range : Select any empty cell --------> ok
We get

New Microsoft Office Excel Worksheet - Microsoft Excel HomeInsertPage LayoutFormulas Data Review View Team Cut E AutoSum Copy B I LI, Ej-0.-A-- -涅涅主Merge & Center, s-% , 168.28 Conditional Form ateCell Formatting as Table Styles Insert Delete Formsat Sort & Find & Format Painter 2 Clear FilterSelect Editing Alignment Cells 17 11.6 23.1 9.9 12.1 13 13.3 Anova: Single Factor 8.1 10.9 12.3 9.9 9.1 15 10.6 11.6 13.9 8.6 18.9 19.1 SUMMARY Count Variance 84.5 10.5625 5.49125 106.8 13.35 14.44857 8 113.5 14.1875 16.92696 SumA 25 15.9 28 ANOVA Source of Varlati P-value F crit Between Gro 57.6325 2 28.81625 2.3449 0.1205 2.575 21 12.28893 31 Within Group 258.0675 32 Total 315.7 23 37 Activate Windows 4 Sheeti Sheet2 Sheet3 11:38 PM 04/16/201g..

1) The analysis of variance test statistic = F = 2.345

2) Critical value = 2.575

3) P-value = 0.1205

4) P-value > 0.10 we faill to reject null hypothesis.

Don't Reject H0