Answer:
C++ code in code snippet :
#include <iostream>
using namespace std;
int numberlen(int i)
{
int n=0;
while(i>0)
{
i=i/10;
n++;
}
return n;
}
int main()
{
int a,b;
cin >>a>>b;
if(a==b)
{
cout <<"A equal to B";
return 0;
}
int n=numberlen(b);
int an=numberlen(a);
int temp=1,flag=0;
for(int i=0;i<n;i++)
{
temp=temp*10;
}
while(an>=n)
{
if(a%temp==b)
{
flag=1;
break;
}
else
{
a=a/10;
an--;
}
}
if(flag==1)
cout <<"A contains B";
else
cout<<"A does not contain B";
return 0;
}
Screenshots of code and output:
Output in another compiler:
Q3 [Number Searching] (25%) Given two non-negative integers A (data type: int) and B (data type:...
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