Question

1. In a survey of 50 people, 25 said they read the Forum and 16 said they listened to the news on NPR. Five of the responders said they read the Forum and listened to the news on NPR. If one of the 50 survey respondents is randomly selected, find the probability that the person read neither the Forum nor listened to NPR? 2. In a survey of 50 people, 25 said they read only the traditional paper form of Forum, while 18 said they did not read the paper version of the Forum. Five of the responders said they neither read the paper Forum nor the Forum online. If one of the 50 survey respondents is randomly selected, find the probability that the person read hath the naner Forum and the online Forum?

Answer 1

1) Given,

Number of people in the survey=50

Number of people who read forum, F=25

P(F)=25/50

Number of people who read NPR, N=16

P(N) =16/50

Number of people who read both, F and N=5

P(F and N) =5/50

P(F or N) =P(F) +P(N)-P(F and N)

P(F or N) = 25/50 + 16/50 -5/50=36/50

Number of people who read neither Forum nor NPR

P(neither F nor N) =1-P(F or N)

P( neither F nor N) = 1- (36/50) =14/50 =0.28

2) Given,

Number of people in the survey =50

Number of people reading traditional version =25

P(traditional)=25/50

Number of people who do not read paper version =18

Therefore,number of people who read online version=50-18=32

P(online)=32/50

Number of people who read neither traditional nor online=5

P(neither traditional nor online)=5/50

P(traditional or online)=1-P(neither traditional nor online)

P(traditional or online)=1-(5/50)=45/50

P(traditional and online)=P(traditional)+P(online)-P(traditional or online)

P(traditional and online)=(25/50)+(32/50)-(45/50)=12/50=0.24