Eighty percent of households in the United States have cable internet. A random sample
of 10 households is selected. What is the probability that at least 6 of the households
selected have cable internet?
A.
0.1209
B.
0.9672
C.
0.8791
D.
0.0328
E.
None of the above
Solution
Given that ,
p = 0.80
q = 1 - p = 1 - 0.80 = 0.20
n = 10
Using binomial probability formula ,
P(X = x) = (n C x) * p x * (1 - p)n - x
P(X 6 ) = 1 - P( x <6)
= 1 - (10 C 0) * 0.80 0 * (0.20)10 - (10 C 1) * 0.80 1 * (0.20)9 - (10 C 2) * 0.80 2 * (0.20)8 - (10 C 3) * 0.80 3 * (0.20)7 - (10 C 4) * 0.80 4 * (0.20)6 - (10 C 5) * 0.80 5 * (0.20)3
=1-0.0328
probability=0.9672
Eighty percent of households in the United States have cable internet. A random sample of 10...
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