Question

Part C - Calculating probabilities in pedigrees of X-linked conditions

The pedigree from Part B is shown below.

$MG_1247598_Part_B_Answer.jpg$

Female III-4 is pregnant via male III-5. The owner of this breeding pair wants to know the probabilities of several possible outcomes for their offspring (IV-3). If you need help with how to approach calculating these probabilities, use the Hint.

Answer each question by dragging the correct label to the appropriate location. Labels can be used once, more than once, or not at all.

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Answer 1

1. What is the probability that IV-3 will have condition A?

\(\frac{2}{3} \times \frac{1}{2} \times \frac{1}{2} \times \frac{2}{3} \times \frac{1}{2} \times \frac{1}{2}=\frac{1}{36}\)

2. What is the probability that IV-3 will have condition B?

\(\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}=\frac{1}{8}\)

3. What is the probability thatIV-3 will have both conditions?

\(\mathbf{1} / \mathbf{2 8 8}\)

4. What is the probability thatIV-3 will have neither condition?

\(245 / 288\)

5. What is the probability that IV-3 will have at least one of the two conditions?

\(43 / 288\)