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Problem 2: A mechanical engineer was asked to design the truss system shown in Figure 2 so that none of the truss members wil
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Answer #1

At Joint A Angle (Far): taw (3) = 36.98 Angle of (EAC) = 59.50 Efx=0 -Fan Cos 36-9 – FacCos 59.5 = 0 - 0 FAB= -0.63 FAC £5 -0At Joint C Efn=0 - fco-Focsin 36:9 + facsin 30.5 =0 Efg=0 Foc cos 36.97 FAC COS 365 0 Foc= -1.071 FAC → Fo= -2.386 F - Foc =

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