Number of moles of I2 = Mass/molar mass = 29.5/254 = 0.1161 moles
Molality = Number of moles of solute/mass of solvent in Kg
=> 0.1161/(109 mL * 0.789 g/mL * 10^(-3))
=> 1.35M
Depression in Freezing Point = i * Kf * m
=> 1 * 1.99 * 1.35
=> 2.686C
New freezing point = -114C - 2.686C
=> -116.686C
Determine the freezing point of a solution that contains 29.5 g of iodine dissolved in 109...
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