a. What is the numerical value of velocity V1?
b. What is the numerical value of velocity V2?
c. what is the value of manometer reading h?
d. What formula can be used to determine h?
a. What is the numerical value of velocity V1? b. What is the numerical value of...
Water flows through a pipe reducer as shown in the figure. If the manometer reading h - 2 m. Find the flow rate in Liters per second. Assume DI-15 cm, D2-10 cm. SG:-0.80 a. What is the effect of the angle θ b. Is this a practical arrangement, if yes why, if not how would you improve it? c. Ca n mercury be used as a manometer fluid in this arrangement? Why, or why not? SG D2 Water Di Water...
بسرعة 1-who ixxcx manometer shown in Fig 3 reads What is the velocity of the water in the pipe if the (c) Find tha water velocity (b) 10 cm? (a) 4 cn in tha Manometer 8 Manoml ( d) Does V in crease of Manomat" decrease in the Pipe alter 4h Manometer İpyes hou, ifnot why 7 Hg 1-who ixxcx manometer shown in Fig 3 reads What is the velocity of the water in the pipe if the (c) Find...
Water is flowing through a horizontal pipe with diameter, D1, at a velocity, V1, and under a pressure, P1. It enters a 900 reducing bend (Shown in grey in Fig 2) that connects to a vertical pipe of diameter, D2. The inlet of the bend is 50 cm above the exit of the bend (as shown in Fig 2). Axes for positive directions of x and z coordinates are provided. Figure 2 Side view of reducing bend from horizontal to...
Three pipes steadily deliver water to a large exit pipe as shown. The velocity at pipe 2, V3-6.00 m/s and the exit flow rate Q4=140 m/hr. If increasing Q, by 20% would increase Q4 by 10%, what is the value of V.? Take 1-3.14 D, -6 cm D-5 cm D-9 cm D-4 cm a) b) V1=5.00 m/s V =4.01 m/s Vi=6.01 m/s V =7.01 m/s c) d)
1. (20 points) Below, a fluid mechanics probiem with two major errors is shown. Water fiows steadily upward through a pipe consisting of two sections with a smooth reducing section. Using the given information below, find the height difference 'h' from the mercury manometer. Friction is negligible in this flow. The density of mercury and water are given as pe 847 Ibm/f3 and pu 62.4 lbm/ft respectiveiy A1 0.08 ft2 42 0.05 ft V1 8 ft/s V2 15 ft/s P,...
this question please in si units. with the process Faculty of Science, Engineering and Technology QUESTION 3 a. (9 marks) Air flows vertically upward in a converging pipe as shown in the figure. A water manome ter is connected to a Pitot tube in the large pipe section, and a piezometer, 1.5m from the datum in the smaller section. The deflection of the water manometer is H=5em. Assume a temperature of 20°Cand atmospheric pressure in the large pipe, and assume...
Observations Process Fluid Manometric Fluid Flowrate (Liter Per Minute) h1 (om of Manometric Fluid) h2 (cm of Manometric Fluid) Water Mercury 5.00 35.3 34.7 Water Mercury 10.00 38.1 33.9 Water Mercury 15.00 37.5 32.5 Water Mercury 20.00 30.5 30.5 Water Mercury 25.00 41.0 28.1 Water Mercury 30.00 25.1 Water Mercury 35.00 48.4 21.0 Water Mercury 40.00 52.4 17.6 Experimental Data Venturi Diameter: 0.006 meter(s) Type of Venturi tube : Welded Tube Nominal Pipe Diameter: 0.25 inch Actual Pipe Diameter: 0.92...
Using Bernoulli's equation, the calculated pressure P0 is: a.) 321213 dyne/cm3 b.) 135263 dyne/cm3 c.) 452647 dyne/cm3 d.) 128513 dyne/cm3 P.. = Pressure Atmospheric time= 7s h1 = 13cm hcl = 6.3 cm Diameter = 11.5cm Reservoir B height = 21 cm h.2 = 13.2 cm h.cpl = y cm h; = 13 lcm P1 = Pressure column h.cp2 = xcm Velocity(v.) Pipe Diameter = 3.6cm P2 = Pressure column Area.p1 Velocity (V2) Тар А hpl = 73.2 cm Pipe...
For #13 how is Tangential acceleration 0 can you solve it please. ( what does V2-V1 equal) For # 8 why is E correct please give detailed explanation. s traveling around a direudla rotary wthich has ra ot 100m certain intant of tme, the car is traveing at asperd n at a rate of 1.00 t h of the following diagrams shows the approsimate direction of the car's loweraln a) b) e) d) 9. The centripetal acceleration of the tar...
CENTRE INDEX NUMBER SECTION B 30 marks] Calculate the discharge through a pipe of diameter 200 mm when the difference of pressure head between the ends of the pipe 500 m apart is 4 m of water. Take the value off= 0.009 in the formula hl= a) 19.5e/s b)2.0es e)03 m's d) 29.3 e/s 2. A scale 1:50 scale model of ship is towed through sea water at a speed of 1 ms. A force of 2 N is required...