Results for this submission Entered Answer Preview X*[e^(2x)] 2e2z (8/3)*(x^3)+C 2 223 + c At least...
(1 point) A first order linear equation in the form y' + p(x) = f(x) can be solved by finding an integrating factor (1) exp(/ pla) de) (1) Given the equation ay' + (1 + 2x) y = 8e 22 find (x) (2) Then find an explicit general solution with arbitrary constant C (3) Then solve the initial value problem with y(1) - ?
A first order linear equation in the form y p(x)y = f(x) can be solved by finding an integrating factor u(x) = exp c) dx (1) Given the equation y 2xy = 10x find H(x) = (2) Then find an explicit general solution with arbitrary constant C у %3 (3) Then solve the initial value problem with y(0) = 3 A first order linear equation in the form y p(x)y = f(x) can be solved by finding an integrating factor...
Please explain, thank you! Results for this submission Entered Answer Preview Result [(-2/5)*(x^2)+(-4/25)*x+(-152/375)]*[e^(2x)] incorrect The answer above is NOT correct. (1 point) Use the method of undetermined coefficients to find one solution of y" +3 y' – 5 y=(-6x2 – 80 – 8) e21. y= ((-2/5)x^(2)+(-4/25)x+(-152/375))e^(2x) help (formulas) Note: The method finds a specific solution, not the general one. Do not include the complementary solution in your answer. Preview My Answers Submit Answers Your score was recorded. You have attempted...
(1 point) A first order linear equation in the form y +p(x)y -f(x) can be solved by finding an integrating factor H(x)exp /p(x) dx (1) Given the equation xy + (1 + 4x) y-6xe_4x find (x)-| xeN4x) (2) Then find an explicit general solution with arbitrary constant C (3) Then solve the initial value problem with y(1)e
(1 point) A first order linear equation in the form y' + p(x)y = f(x) can be solved by finding an integrating factor u(x) = expl (1) Given the equation xy' + (1 +4x) y = 10xe 4* find y(x) = (2) Then find an explicit general solution with arbitrary constant C. y = (3) Then solve the initial value problem with y(1) = e-4 y =
(1 point) A first order linear equation in the form y p(x)yf(x) can be solved by finding an integrating factor x)expp(x) dx (1) Given the equation y' +2y-8x find u(x) - (2) Then find an explicit general solution with arbitrary constant C. (3) Then solve the initial value problem with y(0) 2 y-
(1 point) A first order linear equation in the form y' + p(x)y = f(x) can be solved by finding an integrating factor μ(x) = exp (1) Given the equation y' + 2y = 2 find μ(x) (2) Then find an explicit general solution with arbitrary constant C p(x) dx (3) Then solve the initial value problem with y(0) 2
(1 point) A first order linear equation in the form y' + p(x)y = f(x) can be solved by finding an integrating factor μ(x) = exp ( (1) Given the equation y, +-= 7x4 find μ(x) (2) Then find an explicit general solution with arbitrary constant C p(x) dx (3) Then solve the initial value problem with y(1) = 2
A first order linear equation in the form y' + pay = f() can be solved by finding an integrating factor H(x) = exp() P(a) dx) (1) Given the equation xy' + (1 + 5x) y = 8e 5 sin(4x) find () = (2) Then find an explicit general solution with arbitrary constant C. y = (3) Then solve the initial value problem with y(1) = e-5
A first order linear equation in the form y′+p(x)y=f(x) y p x y f x can be solved by finding an integrating factor μ(x)=exp(∫p(x)dx) μ x exp p x d x (1) Given the equation y′+6y=4 y 6 y 4 find μ(x)= μ x (2) Then find an explicit general solution with arbitrary constant C C . y= y . (3) Then solve the initial value problem with y(0)=3 y 0 3 y= y .