Question

2. A converging lens of 15 cm focal length is placed on an optical bench that is 120 cm long. An object is fixed at 0.0 cm and a screen placed at 120 cm. a) Measuring from the object end of the bench, determine two positions of the lens for which an image will be focused on the screen. b) Find the magnification in each case.
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Answer #1

a) Given that u + v 120cm v Use the lens equati 120-u on zu V av f= 120-11) u(120-u) 120u-u u(120-u) 15 = 15ー- 120 u-120u+18

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