Question

5. Z.so = ? (Z table not required; use your knowledge of Standard Normal curves.) 6. Heights of 20-year-olds. Heights of 20-year-old men vary approximately according to a Normal distribution with p = 176.9 cm and o = 7.1 cm. a. What percentage of U.S. men are at least 6 feet tall? (Six feet - 183 cm) a. 19.49% b. What is the 98th percentile for men's height? a. 194.2 cm and up C. What percentage of men fall within 173 and 183 cm? 30.986% d. Heights of 20-year-old women vary approximately according to a Normal distribution with u = 163.3 cm and o = 6.5 cm. What percentage of U.S. women are at least 6 feet tall? (6 feet = 183 cm) 3.03 e. Would a sample mean of 170 cm be different from the population mean at an alpha of 0.05? Be sure to give your p-value and explain. What is the confidence interval for the sample mean of 170 cm? Does this agree with the p-value, and explain your answer

need the two that are not highlighted

Answer 1

Null Hypothesis , Ho: MA = Mp=lee Alternate Hypothesis ; Ha! Any of the mean is different Now Test statictics Frest statistics using above table Frest = 13.517 Decision on Null Hypotheses Pralue for Flest = 0.000844 Pualue < Nu a as daa.us So Reject the Hell Hypothesis. Conclusion we have sufficient evidence to claim that there is a difference in mean weight loss amount among the three diets at oos level of significance. Answer option ® a 13:47 and yes there i r a difference in diet.

conclusion so but we have not sufficient sufficient evidence to support w claim that sample (Ho and mean of population. is different from sample mean is not different from population ivalue = 0.331951 (8) 2-0.05 CI for, l= 71 72 Now conficlence Interval i M = 170 + (26.095)) x 7.2 diz 170 210.095)*7.1 a value for 7 (0.025) using is 1-96. The Nos mal table All l= 170 1 1.96 x 7.1 MF 170 † 13.92 M= [ 156.08, 183.92] confidence Interval is (156.08 , 183.92 170 cm lies between this interval. yes this agrees with Pvalue. so s so cm