1A survey of 25 grocery stores revealed that the average price of a gallon of milk was $2.98 with a standard error of $0.10.
a. A sample of 25 is selected from a known population of 100 elements.What is the finite population correction factor?
b. If 90% and 95% confidence intervals are developed to estimate the true cost of a gallon of milk, what similarities would they have?
c. What is the 98% confidence interval to estimate the true cost of a gallon of milk?
2 A pharmaceutical company wanted to estimate the population mean of monthly sales for their 250 sales people.Forty sales people were randomly selected.Their mean monthly sales were $10000 with a standard deviation of $1000.construct a 95% confidence interval for the population mean.
3.A bank wishes to estimate the mean balances owed by customers holding MasterCard.Te population standard deviation is estimated to br $300.Ifa 98 percent confidence interval is used and an interval of $75 is desired, how many cardholders should be sampled?
A survey of 25 grocery stores revealed that the average price of a gallon of milk was $2.98 with a standard error of $0.10.
answer =$2.77 to $3.19
b) Both use the same point estimate of the population mean.
Explain: n=25, mean =2.98, standard error = 0.10
For 90% , z value = 1.645
For 95% , z value = 1.96
C.I => x_bar +- z *(standard error)
So everything is the same except the z value for different confidence levels.
So both use the same point estimate.
c)
From normal table for 98% conf interval i.e 1 percentile to 99 percentile the Z value is 2.33
==> Confidence interval = μ±2.33σ ==> [2.747 3.213]
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